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https://github.com/Mbed-TLS/mbedtls.git
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Merge pull request #1408 from mpg/improve-gcd-3.6
[3.6] Make GCD (a lot) less leaky
This commit is contained in:
5
ChangeLog.d/gcd-sign.txt
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5
ChangeLog.d/gcd-sign.txt
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@@ -0,0 +1,5 @@
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Changes
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* The function mbedtls_mpi_gcd() now always gives a non-negative output.
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Previously the output was negative when B = 0 and A < 0, which was not
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documented, and inconsistent as all other inputs resulted in a non-negative
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output.
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@@ -974,8 +974,7 @@ int mbedtls_mpi_random(mbedtls_mpi *X,
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* \brief Compute the greatest common divisor: G = gcd(A, B)
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*
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* \param G The destination MPI. This must point to an initialized MPI.
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* This will be positive unless \p B is 0, in which case \p A
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* will be returned, where \p A could be negative.
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* This will always be positive or 0.
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* \param A The first operand. This must point to an initialized MPI.
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* \param B The second operand. This must point to an initialized MPI.
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*
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147
library/bignum.c
147
library/bignum.c
@@ -430,13 +430,6 @@ cleanup:
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return ret;
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}
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/*
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* Return the number of less significant zero-bits
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*/
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size_t mbedtls_mpi_lsb(const mbedtls_mpi *X)
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{
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size_t i;
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#if defined(__has_builtin)
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#if (MBEDTLS_MPI_UINT_MAX == UINT_MAX) && __has_builtin(__builtin_ctz)
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#define mbedtls_mpi_uint_ctz __builtin_ctz
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@@ -447,22 +440,34 @@ size_t mbedtls_mpi_lsb(const mbedtls_mpi *X)
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#endif
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#endif
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#if defined(mbedtls_mpi_uint_ctz)
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#if !defined(mbedtls_mpi_uint_ctz)
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static size_t mbedtls_mpi_uint_ctz(mbedtls_mpi_uint x)
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{
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size_t count = 0;
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mbedtls_ct_condition_t done = MBEDTLS_CT_FALSE;
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for (size_t i = 0; i < biL; i++) {
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mbedtls_ct_condition_t non_zero = mbedtls_ct_bool((x >> i) & 1);
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done = mbedtls_ct_bool_or(done, non_zero);
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count = mbedtls_ct_size_if(done, count, i + 1);
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}
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return count;
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}
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#endif
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/*
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* Return the number of less significant zero-bits
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*/
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size_t mbedtls_mpi_lsb(const mbedtls_mpi *X)
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{
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size_t i;
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for (i = 0; i < X->n; i++) {
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if (X->p[i] != 0) {
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return i * biL + mbedtls_mpi_uint_ctz(X->p[i]);
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}
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}
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#else
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size_t count = 0;
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for (i = 0; i < X->n; i++) {
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for (size_t j = 0; j < biL; j++, count++) {
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if (((X->p[i] >> j) & 1) != 0) {
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return count;
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}
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}
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}
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#endif
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return 0;
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}
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@@ -1814,103 +1819,51 @@ cleanup:
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}
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/*
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* Greatest common divisor: G = gcd(A, B) (HAC 14.54)
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* Greatest common divisor: G = gcd(A, B)
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* Wrapper around mbedtls_mpi_gcd_modinv() that removes its restrictions.
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*/
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int mbedtls_mpi_gcd(mbedtls_mpi *G, const mbedtls_mpi *A, const mbedtls_mpi *B)
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{
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int ret = MBEDTLS_ERR_ERROR_CORRUPTION_DETECTED;
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size_t lz, lzt;
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mbedtls_mpi TA, TB;
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mbedtls_mpi_init(&TA); mbedtls_mpi_init(&TB);
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/* Make copies and take absolute values */
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MBEDTLS_MPI_CHK(mbedtls_mpi_copy(&TA, A));
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MBEDTLS_MPI_CHK(mbedtls_mpi_copy(&TB, B));
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TA.s = TB.s = 1;
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lz = mbedtls_mpi_lsb(&TA);
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lzt = mbedtls_mpi_lsb(&TB);
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/* Make the two values the same (non-zero) number of limbs.
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* This is needed to use mbedtls_mpi_core functions below. */
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MBEDTLS_MPI_CHK(mbedtls_mpi_grow(&TA, TB.n != 0 ? TB.n : 1));
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MBEDTLS_MPI_CHK(mbedtls_mpi_grow(&TB, TA.n)); // non-zero from above
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/* The loop below gives the correct result when A==0 but not when B==0.
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* So have a special case for B==0. Leverage the fact that we just
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* calculated the lsb and lsb(B)==0 iff B is odd or 0 to make the test
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* slightly more efficient than cmp_int(). */
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if (lzt == 0 && mbedtls_mpi_get_bit(&TB, 0) == 0) {
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ret = mbedtls_mpi_copy(G, A);
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/* Handle special cases (that don't happen in crypto usage) */
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if (mbedtls_mpi_core_check_zero_ct(TA.p, TA.n) == MBEDTLS_CT_FALSE) {
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MBEDTLS_MPI_CHK(mbedtls_mpi_copy(G, &TB)); // GCD(0, B) = abs(B)
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goto cleanup;
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}
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if (mbedtls_mpi_core_check_zero_ct(TB.p, TB.n) == MBEDTLS_CT_FALSE) {
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MBEDTLS_MPI_CHK(mbedtls_mpi_copy(G, &TA)); // GCD(A, 0) = abs(A)
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goto cleanup;
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}
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if (lzt < lz) {
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lz = lzt;
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}
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/* Make boths inputs odd by putting powers of 2 on the side */
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const size_t za = mbedtls_mpi_lsb(&TA);
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const size_t zb = mbedtls_mpi_lsb(&TB);
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MBEDTLS_MPI_CHK(mbedtls_mpi_shift_r(&TA, za));
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MBEDTLS_MPI_CHK(mbedtls_mpi_shift_r(&TB, zb));
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TA.s = TB.s = 1;
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/* Ensure A <= B: if B < A, swap them */
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mbedtls_ct_condition_t swap = mbedtls_mpi_core_lt_ct(TB.p, TA.p, TA.n);
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mbedtls_mpi_core_cond_swap(TA.p, TB.p, TA.n, swap);
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/* We mostly follow the procedure described in HAC 14.54, but with some
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* minor differences:
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* - Sequences of multiplications or divisions by 2 are grouped into a
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* single shift operation.
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* - The procedure in HAC assumes that 0 < TB <= TA.
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* - The condition TB <= TA is not actually necessary for correctness.
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* TA and TB have symmetric roles except for the loop termination
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* condition, and the shifts at the beginning of the loop body
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* remove any significance from the ordering of TA vs TB before
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* the shifts.
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* - If TA = 0, the loop goes through 0 iterations and the result is
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* correctly TB.
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* - The case TB = 0 was short-circuited above.
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*
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* For the correctness proof below, decompose the original values of
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* A and B as
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* A = sa * 2^a * A' with A'=0 or A' odd, and sa = +-1
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* B = sb * 2^b * B' with B'=0 or B' odd, and sb = +-1
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* Then gcd(A, B) = 2^{min(a,b)} * gcd(A',B'),
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* and gcd(A',B') is odd or 0.
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*
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* At the beginning, we have TA = |A| and TB = |B| so gcd(A,B) = gcd(TA,TB).
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* The code maintains the following invariant:
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* gcd(A,B) = 2^k * gcd(TA,TB) for some k (I)
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*/
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MBEDTLS_MPI_CHK(mbedtls_mpi_gcd_modinv_odd(G, NULL, &TA, &TB));
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/* Proof that the loop terminates:
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* At each iteration, either the right-shift by 1 is made on a nonzero
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* value and the nonnegative integer bitlen(TA) + bitlen(TB) decreases
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* by at least 1, or the right-shift by 1 is made on zero and then
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* TA becomes 0 which ends the loop (TB cannot be 0 if it is right-shifted
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* since in that case TB is calculated from TB-TA with the condition TB>TA).
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*/
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while (mbedtls_mpi_cmp_int(&TA, 0) != 0) {
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/* Divisions by 2 preserve the invariant (I). */
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MBEDTLS_MPI_CHK(mbedtls_mpi_shift_r(&TA, mbedtls_mpi_lsb(&TA)));
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MBEDTLS_MPI_CHK(mbedtls_mpi_shift_r(&TB, mbedtls_mpi_lsb(&TB)));
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/* Set either TA or TB to |TA-TB|/2. Since TA and TB are both odd,
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* TA-TB is even so the division by 2 has an integer result.
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* Invariant (I) is preserved since any odd divisor of both TA and TB
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* also divides |TA-TB|/2, and any odd divisor of both TA and |TA-TB|/2
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* also divides TB, and any odd divisor of both TB and |TA-TB|/2 also
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* divides TA.
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*/
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if (mbedtls_mpi_cmp_mpi(&TA, &TB) >= 0) {
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MBEDTLS_MPI_CHK(mbedtls_mpi_sub_abs(&TA, &TA, &TB));
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MBEDTLS_MPI_CHK(mbedtls_mpi_shift_r(&TA, 1));
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} else {
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MBEDTLS_MPI_CHK(mbedtls_mpi_sub_abs(&TB, &TB, &TA));
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MBEDTLS_MPI_CHK(mbedtls_mpi_shift_r(&TB, 1));
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}
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/* Note that one of TA or TB is still odd. */
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}
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/* By invariant (I), gcd(A,B) = 2^k * gcd(TA,TB) for some k.
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* At the loop exit, TA = 0, so gcd(TA,TB) = TB.
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* - If there was at least one loop iteration, then one of TA or TB is odd,
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* and TA = 0, so TB is odd and gcd(TA,TB) = gcd(A',B'). In this case,
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* lz = min(a,b) so gcd(A,B) = 2^lz * TB.
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* - If there was no loop iteration, then A was 0, and gcd(A,B) = B.
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* In this case, lz = 0 and B = TB so gcd(A,B) = B = 2^lz * TB as well.
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*/
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MBEDTLS_MPI_CHK(mbedtls_mpi_shift_l(&TB, lz));
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MBEDTLS_MPI_CHK(mbedtls_mpi_copy(G, &TB));
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/* Re-inject the power of 2 we had previously put aside */
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size_t zg = za > zb ? zb : za; // zg = min(za, zb)
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MBEDTLS_MPI_CHK(mbedtls_mpi_shift_l(G, zg));
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cleanup:
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@@ -1466,10 +1466,10 @@ Test GCD: 6, 0 (1 limb)
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mpi_gcd:"06":"00":"6"
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Test GCD: negative, 0 (null)
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mpi_gcd:"-50000":"":"-50000"
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mpi_gcd:"-50000":"":"50000"
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Test GCD: negative, 0 (1 limb)
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mpi_gcd:"-a782374b2ee927df28802745833a":"00":"-a782374b2ee927df28802745833a"
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mpi_gcd:"-a782374b2ee927df28802745833a":"00":"a782374b2ee927df28802745833a"
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Test GCD: 0 (null), negative
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mpi_gcd:"":"-50000":"50000"
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