Merge pull request #1408 from mpg/improve-gcd-3.6

[3.6] Make GCD (a lot) less leaky
This commit is contained in:
Janos Follath
2025-08-13 19:44:57 +01:00
committed by GitHub
4 changed files with 58 additions and 101 deletions

5
ChangeLog.d/gcd-sign.txt Normal file
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@@ -0,0 +1,5 @@
Changes
* The function mbedtls_mpi_gcd() now always gives a non-negative output.
Previously the output was negative when B = 0 and A < 0, which was not
documented, and inconsistent as all other inputs resulted in a non-negative
output.

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@@ -974,8 +974,7 @@ int mbedtls_mpi_random(mbedtls_mpi *X,
* \brief Compute the greatest common divisor: G = gcd(A, B)
*
* \param G The destination MPI. This must point to an initialized MPI.
* This will be positive unless \p B is 0, in which case \p A
* will be returned, where \p A could be negative.
* This will always be positive or 0.
* \param A The first operand. This must point to an initialized MPI.
* \param B The second operand. This must point to an initialized MPI.
*

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@@ -430,13 +430,6 @@ cleanup:
return ret;
}
/*
* Return the number of less significant zero-bits
*/
size_t mbedtls_mpi_lsb(const mbedtls_mpi *X)
{
size_t i;
#if defined(__has_builtin)
#if (MBEDTLS_MPI_UINT_MAX == UINT_MAX) && __has_builtin(__builtin_ctz)
#define mbedtls_mpi_uint_ctz __builtin_ctz
@@ -447,22 +440,34 @@ size_t mbedtls_mpi_lsb(const mbedtls_mpi *X)
#endif
#endif
#if defined(mbedtls_mpi_uint_ctz)
#if !defined(mbedtls_mpi_uint_ctz)
static size_t mbedtls_mpi_uint_ctz(mbedtls_mpi_uint x)
{
size_t count = 0;
mbedtls_ct_condition_t done = MBEDTLS_CT_FALSE;
for (size_t i = 0; i < biL; i++) {
mbedtls_ct_condition_t non_zero = mbedtls_ct_bool((x >> i) & 1);
done = mbedtls_ct_bool_or(done, non_zero);
count = mbedtls_ct_size_if(done, count, i + 1);
}
return count;
}
#endif
/*
* Return the number of less significant zero-bits
*/
size_t mbedtls_mpi_lsb(const mbedtls_mpi *X)
{
size_t i;
for (i = 0; i < X->n; i++) {
if (X->p[i] != 0) {
return i * biL + mbedtls_mpi_uint_ctz(X->p[i]);
}
}
#else
size_t count = 0;
for (i = 0; i < X->n; i++) {
for (size_t j = 0; j < biL; j++, count++) {
if (((X->p[i] >> j) & 1) != 0) {
return count;
}
}
}
#endif
return 0;
}
@@ -1814,103 +1819,51 @@ cleanup:
}
/*
* Greatest common divisor: G = gcd(A, B) (HAC 14.54)
* Greatest common divisor: G = gcd(A, B)
* Wrapper around mbedtls_mpi_gcd_modinv() that removes its restrictions.
*/
int mbedtls_mpi_gcd(mbedtls_mpi *G, const mbedtls_mpi *A, const mbedtls_mpi *B)
{
int ret = MBEDTLS_ERR_ERROR_CORRUPTION_DETECTED;
size_t lz, lzt;
mbedtls_mpi TA, TB;
mbedtls_mpi_init(&TA); mbedtls_mpi_init(&TB);
/* Make copies and take absolute values */
MBEDTLS_MPI_CHK(mbedtls_mpi_copy(&TA, A));
MBEDTLS_MPI_CHK(mbedtls_mpi_copy(&TB, B));
TA.s = TB.s = 1;
lz = mbedtls_mpi_lsb(&TA);
lzt = mbedtls_mpi_lsb(&TB);
/* Make the two values the same (non-zero) number of limbs.
* This is needed to use mbedtls_mpi_core functions below. */
MBEDTLS_MPI_CHK(mbedtls_mpi_grow(&TA, TB.n != 0 ? TB.n : 1));
MBEDTLS_MPI_CHK(mbedtls_mpi_grow(&TB, TA.n)); // non-zero from above
/* The loop below gives the correct result when A==0 but not when B==0.
* So have a special case for B==0. Leverage the fact that we just
* calculated the lsb and lsb(B)==0 iff B is odd or 0 to make the test
* slightly more efficient than cmp_int(). */
if (lzt == 0 && mbedtls_mpi_get_bit(&TB, 0) == 0) {
ret = mbedtls_mpi_copy(G, A);
/* Handle special cases (that don't happen in crypto usage) */
if (mbedtls_mpi_core_check_zero_ct(TA.p, TA.n) == MBEDTLS_CT_FALSE) {
MBEDTLS_MPI_CHK(mbedtls_mpi_copy(G, &TB)); // GCD(0, B) = abs(B)
goto cleanup;
}
if (mbedtls_mpi_core_check_zero_ct(TB.p, TB.n) == MBEDTLS_CT_FALSE) {
MBEDTLS_MPI_CHK(mbedtls_mpi_copy(G, &TA)); // GCD(A, 0) = abs(A)
goto cleanup;
}
if (lzt < lz) {
lz = lzt;
}
/* Make boths inputs odd by putting powers of 2 on the side */
const size_t za = mbedtls_mpi_lsb(&TA);
const size_t zb = mbedtls_mpi_lsb(&TB);
MBEDTLS_MPI_CHK(mbedtls_mpi_shift_r(&TA, za));
MBEDTLS_MPI_CHK(mbedtls_mpi_shift_r(&TB, zb));
TA.s = TB.s = 1;
/* Ensure A <= B: if B < A, swap them */
mbedtls_ct_condition_t swap = mbedtls_mpi_core_lt_ct(TB.p, TA.p, TA.n);
mbedtls_mpi_core_cond_swap(TA.p, TB.p, TA.n, swap);
/* We mostly follow the procedure described in HAC 14.54, but with some
* minor differences:
* - Sequences of multiplications or divisions by 2 are grouped into a
* single shift operation.
* - The procedure in HAC assumes that 0 < TB <= TA.
* - The condition TB <= TA is not actually necessary for correctness.
* TA and TB have symmetric roles except for the loop termination
* condition, and the shifts at the beginning of the loop body
* remove any significance from the ordering of TA vs TB before
* the shifts.
* - If TA = 0, the loop goes through 0 iterations and the result is
* correctly TB.
* - The case TB = 0 was short-circuited above.
*
* For the correctness proof below, decompose the original values of
* A and B as
* A = sa * 2^a * A' with A'=0 or A' odd, and sa = +-1
* B = sb * 2^b * B' with B'=0 or B' odd, and sb = +-1
* Then gcd(A, B) = 2^{min(a,b)} * gcd(A',B'),
* and gcd(A',B') is odd or 0.
*
* At the beginning, we have TA = |A| and TB = |B| so gcd(A,B) = gcd(TA,TB).
* The code maintains the following invariant:
* gcd(A,B) = 2^k * gcd(TA,TB) for some k (I)
*/
MBEDTLS_MPI_CHK(mbedtls_mpi_gcd_modinv_odd(G, NULL, &TA, &TB));
/* Proof that the loop terminates:
* At each iteration, either the right-shift by 1 is made on a nonzero
* value and the nonnegative integer bitlen(TA) + bitlen(TB) decreases
* by at least 1, or the right-shift by 1 is made on zero and then
* TA becomes 0 which ends the loop (TB cannot be 0 if it is right-shifted
* since in that case TB is calculated from TB-TA with the condition TB>TA).
*/
while (mbedtls_mpi_cmp_int(&TA, 0) != 0) {
/* Divisions by 2 preserve the invariant (I). */
MBEDTLS_MPI_CHK(mbedtls_mpi_shift_r(&TA, mbedtls_mpi_lsb(&TA)));
MBEDTLS_MPI_CHK(mbedtls_mpi_shift_r(&TB, mbedtls_mpi_lsb(&TB)));
/* Set either TA or TB to |TA-TB|/2. Since TA and TB are both odd,
* TA-TB is even so the division by 2 has an integer result.
* Invariant (I) is preserved since any odd divisor of both TA and TB
* also divides |TA-TB|/2, and any odd divisor of both TA and |TA-TB|/2
* also divides TB, and any odd divisor of both TB and |TA-TB|/2 also
* divides TA.
*/
if (mbedtls_mpi_cmp_mpi(&TA, &TB) >= 0) {
MBEDTLS_MPI_CHK(mbedtls_mpi_sub_abs(&TA, &TA, &TB));
MBEDTLS_MPI_CHK(mbedtls_mpi_shift_r(&TA, 1));
} else {
MBEDTLS_MPI_CHK(mbedtls_mpi_sub_abs(&TB, &TB, &TA));
MBEDTLS_MPI_CHK(mbedtls_mpi_shift_r(&TB, 1));
}
/* Note that one of TA or TB is still odd. */
}
/* By invariant (I), gcd(A,B) = 2^k * gcd(TA,TB) for some k.
* At the loop exit, TA = 0, so gcd(TA,TB) = TB.
* - If there was at least one loop iteration, then one of TA or TB is odd,
* and TA = 0, so TB is odd and gcd(TA,TB) = gcd(A',B'). In this case,
* lz = min(a,b) so gcd(A,B) = 2^lz * TB.
* - If there was no loop iteration, then A was 0, and gcd(A,B) = B.
* In this case, lz = 0 and B = TB so gcd(A,B) = B = 2^lz * TB as well.
*/
MBEDTLS_MPI_CHK(mbedtls_mpi_shift_l(&TB, lz));
MBEDTLS_MPI_CHK(mbedtls_mpi_copy(G, &TB));
/* Re-inject the power of 2 we had previously put aside */
size_t zg = za > zb ? zb : za; // zg = min(za, zb)
MBEDTLS_MPI_CHK(mbedtls_mpi_shift_l(G, zg));
cleanup:

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@@ -1466,10 +1466,10 @@ Test GCD: 6, 0 (1 limb)
mpi_gcd:"06":"00":"6"
Test GCD: negative, 0 (null)
mpi_gcd:"-50000":"":"-50000"
mpi_gcd:"-50000":"":"50000"
Test GCD: negative, 0 (1 limb)
mpi_gcd:"-a782374b2ee927df28802745833a":"00":"-a782374b2ee927df28802745833a"
mpi_gcd:"-a782374b2ee927df28802745833a":"00":"a782374b2ee927df28802745833a"
Test GCD: 0 (null), negative
mpi_gcd:"":"-50000":"50000"